6b^2-5=29b

Solution for 6b^2-5=29b equation:

6b^2-5=29b

We move all terms to the left:

6b^2-5-(29b)=0

a = 6; b = -29; c = -5;
Δ = b2-4ac
Δ = -292-4·6·(-5)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*6}=\frac{-2}{12}
=-1/6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*6}=\frac{60}{12}
=5
$